Question

In a right angled triangle if hypotenuse = 10cm, base= 8cm then, find the perpendicular using Pythagoras theorem

Answer 1

Answer:

hypoteneus (h)=10 cm

base (b)=8cm

perpendicular(p)=?

now,

p2=h2-b2

p2=10 square -8 square

p=root under 10square-8square

p=root under 100-64

p=root under36

p=root under 6 square

p=6(root under and square will be cut)

therefore,perpendicular(p)=6cm

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Hypotenuse =10 cm

base =8cm

(P)²=(H)²-(B)²

(P)²=(10)²-(8)²

P = under root (10)²-(8)²

P =under root 100-64

P =under root 36

P =6 cm