In a right angled triangle,if hypotenuse is 10 cm
& the ratio of other two sides is 3:4. Find the sides.
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Given hypotenuse, h = 20 cm
Ratio of other two sides, a:b = 4:3
Let altitude of the triangle be 4x and base be 3x.
According to Pythagoras theorem,
h2 = b2+a2
202 = (3x)2+(4x)2
400 = 9x2+16x2
25x2 = 400
x2 = 400/25
x2 = 16
Taking square root on both sides
x = 4
so base, b = 3x = 3×4 = 12
altitude, a = 4x = 4×4 = 16
Hence the other sides are 12 cm and 16 cm.
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