Question

In a right-angled triangle, if M is the mid-point of the hypotenuse AC, prove that AM = BM = CM.​

Answer 1

Answer:

Draw a parallel line from point 'M' to mid point of AB, name it as 'N'. (By Basic Proportionality Therom) We can say that if a line parallel to the third side that is base 'BC' then, the line passes through the midpoints of other two sides that are 'AB', 'AC'. So, AM/AC IS EQUAL TO AN/AB