In a right-angled triangle, if the lengths of the sides containing the right angle are 20cm and 21cm, then the length of its hypotenuse is...?
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Answer:
Area of any triangle = 1/2 * one side * corresponding altitude
=> 20 = 1/2 * 4 * a
=> a = 20/2 = 10cm
So, now, sides of right triangle = 4cm & 10cm
=> hypotenuse = √(4² + 10²) = √116 = 2√29 cm
Now, again area of this right triangle = 1/2 * hypotenuse * corresponding altitude
=> 20 = 1/2 * 2√29 * h
=> h = 20/√29 = 20√29/29 cm = (20 * 5.38)/29 = 3.71 cm ( approx)
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49cm
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