Question

In a right angled triangle length of base is 4 cm and its perpendicular is 3 cm find the hypotenuse of cos_theta​

Answer 1

Answer:

Hypotenuse will be 5

Explanation:

As it is a right angle triangle, we can say that

3^2 + 4^2 = hypotenuse^2 Pythagorus theorem

9 + 16 = hyp^2

hypotenuse = √25 = 5

You can write the formula before substituting values if You want. Cos theta can be obtained by substituting the values.

Answer 2

Given :-

• In a right angled triangle length of base is 4 cm and it's perpendicular is 3 cm.

To Find :-

• What is the value of cose.

Formula Used :-

$\longmapsto \sf\boxed{\bold{\pink{{(Hypotenuse)}^{2} =\: {(Perpendicular)}^{2} + {(Base)}^{2}}}}$

$\longmapsto \sf\boxed{\bold{\pink{Cos\theta =\: \dfrac{Base}{Hypotenuse}}}}$

Solution :-

• First, we have to find the value of Hypotenuse :

Given :

$\sf{Perpendicular = 3 cm}$

$\sf{Base = 4 cm}$

According to the question by using the formula we get,

$\implies \sf {(Hypotenuse)}^{2} =\: {(3)}^{2} + {(4)}^{2}$

$\implies \sf {(Hypotenuse)}^{2} =\: 3 \times 3 + 4 \times 4$

$\implies \sf {(Hypotenuse)}^{2} =\: 9 + 16$

$\implies \sf {(Hypotenuse)}^{2} =\: 25$

$\implies \sf Hypotenuse =\: \sqrt{25}$

$\implies \sf\bold{\green{Hypotenuse =\: 5\: cm}}$

Hence, the hypotenuse is 5 cm

.

Now, we have to find the value of cose :

Given :

Base = 4 cm

Hypotenuse = 5 cm

According to the question by using the formula we get,

$\leadsto \sf Cose =\: \dfrac{Base}{Hypotenuse}$

$\implies \sf\bold{\red{Cose =\: \dfrac{4}{5}}}$

$\therefore$ The value of cose is 4/5.