Question

in a right angled triangle length of hypotence and one of the side are 10 cm. and 6 cm. respectively, then find the length of other side.​

Answer 1

Answer:

Let's take

H-10cm

P-6cm

B-?

Phyta-H^2=p^2+b^2

(10)^2=(6)^2+b^2

100=36+b^2

100-36=b^2

64=b^2

b^2=64

b=root64

b=root4×4×4

b=4×2

b=8

so the other side length is 8 cm

Answer 2

Answer:

According to pythogoras theorem

${h}^{2} = \: {p}^{2} \: + \: {b}^{2}$

${10 \:}^{2} \: = \: {6 \: }^{2} \: + \: {b}^{2}$

$100 \: = \: 36 \: + \: {b}^{2}$

${b \:}^{2} \: = 100 - 36$

${b }^{2} \: = \: 64$

$b \: = \: \sqrt{64}$

$b = \: 8cm$

Hence the other side of the right angled triangle

= 8 cm