Question

In a right angled triangle lengths of hypotenuse and one of the sides are 10 cm. and 6 cm. respectively, then find the length of other side​

Answer 1

Step-by-step explanation:

Let's take

H-10cm

P-6cm

B-?

Phyta-H^2=p^2+b^2

(10)^2=(6)^2+b^2

100=36+b^2

100-36=b^2

64=b^2

b^2=64

b=root64

b=root4×4×4

b=4×2

b=8

so the other side length is 8 cm

Answer 2

Concept

Pythagoras theorem states that “In a right-angled triangle,  the square of the hypotenuse side is equal to the sum of squares of the other two sides“ .The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°

Given

We have given the length of the hypotenuse 10cm and the length of the perpendicular 6cm .

Find

We are asked to determine the length of the base.

Solution

We will solve this question by applying Pythagorean theorem

$(Hypotenuse)^{2} =(Perpendicular)^{2} +(Base)^{2}$.....(1)

Putting $Hypotenuse=10$ and $Perpendicular=6$ in equation (1) , we get

$(10)^{2} =(6)^{2} +(Base)^{2} \\100=36+(Base)^{2} \\(Base)^{2}=64\\(Base)=8$

Hence, the length of the Base is is 8cm.

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