Question

in a right angled triangle, one of the acute angle is two- thirds of other, find the angel of the triangle​

Answer 1

Answer:

The answer will be :

∠1 = 90° ; ∠2 = 54° ; ∠3 = 36° ;

Step-by-step explanation:

We have given;

                     ∠1 = 90° (since it's a right angled triangle);

Let one of the angle of acute angle of the right angled triangle be x;

hence,                     ∠2 = x;

  Now, according to your question, another acute angle is 2/3 of the previous one;

hence,                 ∠3 = 2/3 * x;

Now, we know that the sum of angles in a triangle is 180° (angle sum property);

Hence, we can write,

                       ∠1 + ∠2 + ∠3 = 180°;

Now, we put the respective values of the angles;

Thus,                     90° + x + 2x/3 = 180°;

Now, we have to solve this to get our answer;

SO,                          x + 2x/3 = 180° - 90°;

                              (3x + 2x) / 3 = 90°;

                               5x / 3 = 90°;

                              5x = 90° * 3;

                               x = 270°/5;

                               x = 54°;

So, here we go. Our respective angles will be:

⇒∠1 = 90°  (as it is already given);

⇒∠2 = 54°  (we had taken x = ∠2);

⇒∠3 = 2/3 * ∠2;

        = 2/3 * 54°;

        = 2 * 18°;

        = 36°

That's all.

Answer 2

Answer:

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