Question

In a right angled triangle one of the sides forming the right angle is 4 cm more than twice
the length of the other side. If the area of the triangle is 120 cm. Find the perameter of
the triangle.​

Answer 1

Answer:

we know that area of triangle equal to half into base into height equal to half into X into 2 X + 4 As given area of triangle is 120 square centimetre therefore 122 half into 2 X square + 4 x therefore 2 X square + 4 X equal to 42 X square + 4 x minus 2 XL equal to zero therefore to write inside the (X square + 2 X - 120 equal to zero therefore X square + 2 x minus 1 equal to zero by factorisation method X square + 12 x minus 10 x minus 1 equal to zero X Into X + 12 - 10 into X + 12 equal to zero X + 12 x minus 3 equal to zero X equal to minus 12 X equal to 10 but we know that site cannot be negative X equal to minus 12 is not acceptable two sides of triangle are X= 10cm and 2X+4=24cm.

by pythagorus theoram we get AC=26cm. perimeter= 24+26+10=60cm

Step-by-step explanation: