In a right angled triangle PQR, = 90° l(PQ) = 12cm, l(PR) = 20cm, find the
length of seg QR
Answers
Answered by
1
Answer:
PQR right angle triangle so PR^2= PQ^2 +QR^2
Step-by-step explanation:
- QR^2= 400-144= 256
- QR=16
Answered by
1
Answer:
16
Step-by-step explanation:
According to Pythagoras theorem,
here is PQ which is 12
PR is 20
Therefore > (12)*(12) + (QR)*(QR) = (20)*(20)
144+ QR square = 400
QR square= 400-144
- QR Square=256
- therefore QR=16
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