Question

In a right angled triangle PQR, ∠ P = 90°
PR = 8 cm, QR = 17 cm. Find sin Q, cos Q, tan Q and cot Q.​

Answer 1

Answer:

sinQ= 8/17

cosQ = 15/17

tanQ = 8/15

cotQ = 15/8

Step-by-step explanation:

PR = 8cm, QR = 17cm,

Since triangle is right angle triangle. By using Pythagoras theorem we can find the length of base.

so, PQ = √{( QR)^2 - (PR)^2} = √{(17)^2 - (8)^2} = 15

sinQ= 8/17

cosQ = 15/17

tanQ = 8/15

cotQ = 15/8