Question

In a right angled triangle PQR right angled at Q.IF PQ=8cm and PR= 10cm .find QR
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Answer 1

Answer:

6

Step-by-step explanation:

QR²+PQ²=PR²

QR²=100-64

=36

QR=6

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Answer 2

Step-by-step explanation:

using Pythagoras theorem,

(QR)^2=(PR)^2-(PQ)^2

(QR)^2=(10)^2-(8)^2

(QR)^2=100-64

QR=√36

QR=6