In a right-angled triangle, right angled at B, if AB = 5 cm and AC = 13 cm, then BC is equal to
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Note:
Refer the attachment!
⭐Given:
- ∆ABC is a right angled triangle.
- <B=90°
- AB=5cm
- AC=13cm
⭐To Find:
- BC=?
⭐Solution:
It is given that ∆ABC is a right angled triangle.
Therefore,
By Pythagoras therom,
(AC) ²=(AB) ²+(BC) ²
(13)²=(5) ²+(BC) ²
169=25+(BC) ²
(BC) ²=169-25
(BC) ²=144
BC=12 cm
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Step-by-step explanation:
AB^2+AC^2=BC^2
5^2+AC^2=13^2
25 +AC^2=169
AC^2=169-25
AC^2=144
AC=√144
AC=12
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