Math, asked by rohini6560, 3 months ago

In a right angled triangle secA = 12
5
, find the remaining trigonometrical ratios

Answers

Answered by Anonymous
0

Answer:SinA=P/H=12/ 13CosA=B/H=5/13CosecA=H/P=13/12SecA=H /B=13/ ... the other trigonometric Ratio can be found By using ... SecA = 1/CosA = 1/(5/13) = 13/15...

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