Math, asked by riyasharma49, 5 months ago

in a right angled triangle tanA =6/8 find : CosA,SinA and CosA + SinA

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Answered by gurmitjuly

0

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Answered by purnimadebbarma169

1

Step-by-step explanation:

given,

tanA=6/8=P/b

applying phythagoras theorem

= 36 + 64

= √100

= 10

therefore,h= 10

now,

cos A=b/h

=8/10

sin A=P/h=6/10

cosA+sinA=8/10 + 6/10=14/10

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