Question

in a right angled triangle ,the acute angles are in the ratio 2:7 the acute angles are ​

Answer 1

Answer:

let 2:7 be 2x and 7x

ATQ,

2x + 7x + 90° = 180° (A.S.P of ∆ )

9x + 90° = 180°

9x = 180° - 90°

9x = 90°

x = 90 °/9

x = 10°

therefore, 2x = 2 × 10° = 20° and 7x = 7× 10° = 70°

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Answer 2

Answer:

2x=20 and 7x= 70

Step-by-step explanation:

let the common multiple be x

:. 2x+7x =90°.........(addition of acute angles of right angle. triangle )

:. 9x=90°

:.x=90°/9

:.x= 10

now, by substituting value of x in ratios

2x=2× 10= 20°

and

7x= 7×10= 70°