In a right- angled triangle, the base of a right angled triangle is 12 cm and its hypotenuse is 13 cm. How do you find the area of the triangle?
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In a right- angled triangle, the base of a right angled triangle is 12 cm and its hypotenuse is 13 cm. How do you find the area of the triangle?
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It is given that
ABC is a right angled triangle
BC = 12 cm and AB = 13 cm
Using the Pythagoras theorem
AB2 = AC2 + BC2
Substituting the values
132 = AC2 + 122
By further calculation
AC2 = 132 – 122
So we get
AC2 = 169 – 144 = 25
AC = √25 = 5 cm
We know that
Area of triangle ABC = ½ × base × height
Substituting the values
= ½ × 12 × 5
= 30 cm2
Similarly
Perimeter of triangle ABC = AB + BC + CA
Substituting the values
= 13 + 12 + 5
= 30 cm
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