Question

In a right angled triangle the length of its base is 4 cm and perpendicular is 3 cm . Find its hypotenuse

Answer 1

Answer:

Explanation:

Base =4cm  and  perpendicular =3cm

Through Pythagorus theorem,

         H^2=P^2+B^2

         H^2= 9+ 16

         H=5

Answer 2

Given,

• The length of the base of a right angled-triangle = 4 cm
• Perpendicular distance of the right-angled triangle = 3 cm

To find,

• We have to find the hypotenuse of the right-angled triangle.

Solution,

We can simply find the hypotenuse of the right-angled triangle by using the Pythagoras theorem.

       (H)² = (B)²+(P)²        (*)

where 'H' is the hypotenuse of the right-angled triangle, 'B' is the base of the right-angled triangle, and 'P' is the perpendicular distance of the right-angled triangle.

The length of the base of a right angled-triangle = 4 cm

Perpendicular distance of the right-angled triangle = 3 cm

Using (*), we get

         (H)² = (4)² + (3)²

         (H)² = 16 +9

         (H)² = 25

         (H)  =  $\sqrt{25}$

        (H)  = 5 cm

Hence, in a right-angled triangle, the length of its base is 4 cm and perpendicular is 3 cm, then the hypotenuse of the right-angled triangle is 5 cm.