In a right angled triangle the length of theone side containing the right angle is greater than twice the length if the other by 4cm.the area of the the triangle is 80 centimetre square. Find the lengths of the sides containing the right angle.
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Step-by-step explanation:
in a right angle triangle
let the base be "x" so the other side which is height is "2x+4"
now, the area of the traingle is 1/2*base*height=80
on putting the value we get,
=>1/2*x*(2x+4)=80
=>2xsquare+4x/2=80
=>2x square +4x=80*2
=>2xsquare +4x=160
=>2xsquare +4x-160=0
=>2(xsquare+2x-80)=0
=>xsquare+2x-80=0
now solve it you will get your will
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