Question

In a right angled triangle the lengths of sides making right angle are 10cm and 24cm. Find the length of the hypotenuse​

Answer 1

Thanks for your question…

A right angled triangle follows the Pythagoras Theorem. That is—

(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2.

H^2 = [P^2] + [B^2].

It is given that length of the Hypotenuse is 26 cm & that of Perpendicular is 24 cm.

Putting the above values in the formula, we get,

(26)^2 = (24)^2 + (Base)^2.

=> 676 = 576 + Base^2.

=> Base^2 = 676–576

=> Base^2 = 100

=>Base = sqrt(100) = 10 cm.

Therefore, the base of the triangle is 10 cm in length.

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Answer 2

SOLUTION :

$in \: right \: angled \: triangle \: \\ \\ (hypotenuse) {}^{2} = (sum \: of \: squares \: of \: other \: two \: sides) \\ \\ = > (hyp) {}^{2} = (10) {}^{2} + (24) {}^{2} \\ \\ = > (hyp) {}^{2} = 676 \\ \\ = > hypotenuse = \sqrt{676} = 26 \\ \\ \: thus \: legth \: of \: hypotenuse \: = 26cm$

HOPE IT HELPS !!!!!