Question

In a right angled triangle, the sides forming the right angle differ by 7 cm. Find its sides, if its perimeter is 40cm.

Answer 1

Let the length of the base = x
Then,
      hypotenuse = 33-2x
       perpendicular = x+7
So, by pythagoras theorem,
1089+4x²-132x=x²+x²+49+14x
 2x²+1040-146x=0
 x²+520-73x=0
 x²-73x+520=0
 x²-8x-65x+520=0
 x(x-8)-65(x-8)=0
 (x-8)(x-65)=0
 x-8=0 or x-65=0
 therefore, x=8 or x=65
 x={8,65}

If x=8
the sides are 8,15,17 cm.

If x=65
the sides are 65,72,-137 cm.

Since, the answer for second value is in negative we will negotiate it.

Therefore, x=8 and the sides are 8 cm , 15 cm & 17 cm.

Answer 2

Answer:

8,15,17

make me brainlist