In a right-angled triangle, the square of hypotenuse is equal to the sum of the squares of the two sides. Given that
Angle b
of triangle ABC
is an acute angle and AD is perpendicular to bc
. Prove that AC2=AB2+BC2-2BC*CD
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Answer:
In a right-angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides
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