Math, asked by tanishqgangwal, 3 months ago

In a right-angled triangle, the square of hypotenuse is equal to the sum of the squares of the two sides. Given that
Angle b

of triangle ABC

is an acute angle and AD is perpendicular to bc

. Prove that AC2=AB2+BC2-2BC*CD​

Answers

Answered by okieedokiee
0

Answer:

In a right-angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides

Step-by-step explanation:

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