. In a right-angled triangle, with right if AB = 6 units, BC = 8 units then AC = 10 units, then the right angle is at
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Question :- In a right-angled triangle, with right if AB = 6 units, BC = 8 units then AC = 10 units, then the right angle is at ?
Solution :-
given that,
- AB = 6 units.
- BC = 8 units.
- AC = 10 units.
- ∆ABC is a right angled ∆ .
so,
→ (Perpendicular)² + (Base)² = (Hypotenuse)²
→ 6² + 8² = 10²
→ 36 + 64 = 100
→ 100 = 100 .
now, we know that,
- Angle opposite to hypotenuse is equal to 90° .
we can conclude that, AC is the hypotenuse of the right angled ∆ABC .
therefore, right angle is at vertex B.
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