In a right angled triangle with sides a and b and hypotenuse c, the altitude drawn on the hypotenuse is x. Prove that ab = cx
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Step-by-step explanation:
It is given that AB=a, BC=b, AC=c and BE=x.
Also, ABC is a right angled triangle, which is right angled at B and BE⊥AC.
From ΔABC and ΔAEB, we have
∠ABC=∠AEB=90°
∠BAC=∠EAB(Common)
Thus, By AA similarity,
ΔABC is similar to ΔAEB.
Therefore, using the similarity condition, we have
AC/AB = BC/EB
c/a=b/x
cx=ab
hence , ab=cx
thus proved..
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