Question

In a right angled triangle XYZ ∠Y=90°, XY=6cm, XZ=10cm, find YZ​

Answer 1

Answer:

》By using Pythagoras theorm.

》(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2

》Here, hypotenuse = 10cm, Perpendicular = 6cm and Base = x

》(10)^2 = (6)^2 + (x)^2

》100 = 36 + x^2

》100 - 36 = x^2

》x^2 = 64

》x = root of 64

》x = 8

》So YZ = 8cm

》May your doubt be clarified by me...

Answer 2

Step-by-step explanation:

${xz}^{2} = {xy}^{2} + {yz}^{2} \\ {yz}^{2} = {xz}^{2} - {xy}^{2} \\ {yz}^{2} = {10}^{2} - {6}^{2} \\ {yz}^{2} = 100 - 36 \\ yz = \sqrt{64} \\ yz = 8$