in a right isosceles triangle find the value of all interior angles as well as exterior angles
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The interior angles would be :-
1.90°
2.(180-90)/2=90/2=45°[Sum of angles=180° =x+x+90=180=2x=90°]
3Angle 3=Angle 2=45°
Exterior angle=180-interior angle.
The exterior angles are:-
1.180°-90°=90
2.180°-45°=135°
3.180°-45°=135°
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