In a right triangle abc angle b is 90 and angle a is 30 Ac 8 cm find ab and Ac
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Answer:
angle A = 90° and angle B 30°
=> angle C = 90° - 30° = 60°
=> BC is the hyp = 8 cm long
AC = 8/2 =4cm (sin30° = AC/hp => 8sin30°=AC
AC = 8×1/2 = 4
AB = √(BC^2 - AC^2) = √(8^2 - 4^2) = √(64-16) = 6.93cm
AC = 4 cm
AB = 6.93 cm
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Ac 4cm , AB 6.93 cm mark me as brainliest
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