In a right triangle ABC , angle C is 90 , If AB= 26 m , BC = 10 m , the perimeter of triangle ABC is
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Answer:
60 is the answer..
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Answer:
given it is a right angled triangle
=> (AB)^2 = (BC)^2 + (AC)^2 { pythagoreas th.m}
=> (26)^2 = (10)^ 2 + (AC)^2
=> (AC)^2 = 676 - 100
=> (AC) = √576 = 24m
∴ perimeter of ΔACB = (AB) + (BC) + (AC)
= 26 + 10 + 24 = 60m
Hope it helps u !!!!!
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