in a right triangle ABC, \b = 90, AC =13 ,NC =5 find ab
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Answered by
0
If NC =BC
then,
By Pythagoras theorem,
13²=5²+ab²
169-15=ab²
144=ab²
12=ab
I hope this much will help you
then,
By Pythagoras theorem,
13²=5²+ab²
169-15=ab²
144=ab²
12=ab
I hope this much will help you
Answered by
0
By Pythagoras Theorem
ab2+bc2=ac2
ab2=ac2-bc2
ab2=13square-5square
ab2=169-25
ab=12cm
ab2+bc2=ac2
ab2=ac2-bc2
ab2=13square-5square
ab2=169-25
ab=12cm
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