Math, asked by priya35687, 12 hours ago

In a right triangle ABC, B=90°
1. AC=12cm, BC=10cm, AB=?

2. AB=10cm, BC=12cm, AC=?

3. AB=?, BC=20, AC=22cm

4. AB=15cm, BC=17cm, AC=? ​

Answers

Answered by luckymagma629
0

Answer:

1.  (AB)^2= (AC)^2-(BC)^2

    (AB)^2= (12)^2-(10)^2

    (AB)^2= 144-100

    (AB)^2=44

     AB=root square 44= 6cm (6.633)

2.  (AC)^2= (BC)^2+(AB)^2

    (AC)^2= (12)^2+(10)^2

    (AC)^2= 144+100

    (AC)^2= 244

     AC=root square 244= 15cm (15.620)

3.   (AB)^2= (AC)^2-(BC)^2

    (AB)^2= (22)^2-(20)^2

    (AB)^2= 484-400

    (AB)^2=84

     AB=root square 84= 9cm (9.165)

4.  (AC)^2= (BC)^2+(AB)^2

    (AC)^2= (17)^2+(15)^2

    (AC)^2= 289+225

    (AC)^2= 514

     AC=root square 514= 22cm (22.67156)

Take these as notes:

In right angled triangle:

(Hypotenuse)^2= (Leg)^2  +  (leg)^2

(Leg)^= (Hypotenuse)^2 - (Leg)^2

And after solving the formulas above, take the root square of the answer

Hope this helps

 

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