In a right triangle ABC, B=90°
1. AC=12cm, BC=10cm, AB=?
2. AB=10cm, BC=12cm, AC=?
3. AB=?, BC=20, AC=22cm
4. AB=15cm, BC=17cm, AC=?
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Answer:
1. (AB)^2= (AC)^2-(BC)^2
(AB)^2= (12)^2-(10)^2
(AB)^2= 144-100
(AB)^2=44
AB=root square 44= 6cm (6.633)
2. (AC)^2= (BC)^2+(AB)^2
(AC)^2= (12)^2+(10)^2
(AC)^2= 144+100
(AC)^2= 244
AC=root square 244= 15cm (15.620)
3. (AB)^2= (AC)^2-(BC)^2
(AB)^2= (22)^2-(20)^2
(AB)^2= 484-400
(AB)^2=84
AB=root square 84= 9cm (9.165)
4. (AC)^2= (BC)^2+(AB)^2
(AC)^2= (17)^2+(15)^2
(AC)^2= 289+225
(AC)^2= 514
AC=root square 514= 22cm (22.67156)
Take these as notes:
In right angled triangle:
(Hypotenuse)^2= (Leg)^2 + (leg)^2
(Leg)^= (Hypotenuse)^2 - (Leg)^2
And after solving the formulas above, take the root square of the answer
Hope this helps
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