Math, asked by julius2768, 9 months ago

In a right triangle ABC cb =90 degree if AB = 5cm , bc = 12 cm then find AC

Answers

Answered by Anonymous
10

{\underline{\underline{\red{\sf{Given:}}}}}

  • There is a right angled ∆ABC.
  • The measure of AB = 5cm.
  • The measure of BC =12cm.

{\underline{\underline{\red{\sf{To\:Find:}}}}}

  • Measure of side AC .

{\underline{\underline{\red{\sf{Concept\;Used:}}}}}

  • We will make use of Pythagoras Theorm.

{\underline{\underline{\red{\sf{Answer:}}}}}

We are given a right angled triangle .

So , 'Pythagoras Theorem' is applicable here .

Now Pythagoras Theorem is stated as :

  • The square of hypotenuse is equal to sum of square of other two sides.

\large{\boxed{\red{\sf{\hookrightarrow AC^{2}=AB^{2}+BC^{2}}}}}

(For figure refer to attachment:)

\sf{\implies AC^{2}=(5cm)^{2}+(12cm)^{2}}

\sf{\implies AC^{2}=25cm^{2}+144cm^{2}}

\sf{\implies AC^{2}=169cm^{2}}

\sf{\implies AC=\sqrt{169cm^{2}}}

{\underline{\boxed{\purple{\sf{\longmapsto AC=13cm}}}}}

Therefore length of side AC is 13cm.

Note:

  1. Here 5 cm ,12cm & 13cm are Pythagorean Triplet.
Attachments:
Answered by mohammedmushahid596
0

Answer:

{\underline{\underline{\red{\sf{Given:}}}}}

Given:

There is a right angled ∆ABC.

The measure of AB = 5cm.

The measure of BC =12cm.

{\underline{\underline{\red{\sf{To\:Find:}}}}}

ToFind:

Measure of side AC .

{\underline{\underline{\red{\sf{Concept\;Used:}}}}}

ConceptUsed:

We will make use of Pythagoras Theorm.

{\underline{\underline{\red{\sf{Answer:}}}}}

Answer:

We are given a right angled triangle .

So , 'Pythagoras Theorem' is applicable here .

Now Pythagoras Theorem is stated as :

The square of hypotenuse is equal to sum of square of other two sides.

\large{\boxed{\red{\sf{\hookrightarrow AC^{2}=AB^{2}+BC^{2}}}}}

↪AC

2

=AB

2

+BC

2

(For figure refer to attachment:)

\sf{\implies AC^{2}=(5cm)^{2}+(12cm)^{2}}⟹AC

2

=(5cm)

2

+(12cm)

2

\sf{\implies AC^{2}=25cm^{2}+144cm^{2}}⟹AC

2

=25cm

2

+144cm

2

\sf{\implies AC^{2}=169cm^{2}}⟹AC

2

=169cm

2

\sf{\implies AC=\sqrt{169cm^{2}}}⟹AC=

169cm

2

{\underline{\boxed{\purple{\sf{\longmapsto AC=13cm}}}}}

⟼AC=13cm

Therefore length of side AC is 13cm.

Note:

Here 5 cm ,12cm & 13cm are Pythagorean Triplet.

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