Question

In a right triangle ABC in which angle B=90°, a circle is drawn with AB as diameter intersecting the hypotenuse AC at P. Prove that the tangent to the circle at P bisects BC.​

Answer 1

Answer:

∠ABC = 90°. A circle is drawn with AB as diameter intersecting AC in P, PQ is the tangent to the circle which intersects BC at Q. Join BP. PQ and BQ are tangents drawn from an external point Q.

Step-by-step explanation:

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