In a right triangle ABC, <A=90 degrees and ∆ABC is also an isosceles triangle with AB=AC, what are the measures of <ABC and <ACB?
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the measures of remaining angles are 45°
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Step-by-step explanation:
since AB = AC. (given)
so, angle ABC = angle ABC. ....(1)
Now in triangle ABC-
LA +LB + LC = 180. (angle sum property)
90+LB+LB. =180. (from eq 1)
2LB = 180-90
LB = 90/2
LB = 45
But LABC = ACB = 45
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