Question

in a Right triangle ABC Right angle at
c au which AB= 13 , BC = 5cm détermine
the value cos square b + sin square A​

Answer 1

Answer:

AC=SQUT OF[(AB)^2- (BC)^2]

AC= 12cm

Now sin2A=(5/13)^2

Cos2B=(5/13)^2

ATQ

25/169+25/169

=50/169

Answer 50/169