In a right triangle abc right angle at c if tana=1 than verify that 2sina×cosa=1
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TanA=1=Tan45°
A=45°.C=90°B=90-45=45°
hence its verified
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⇒ Given :- ABC is a right angled triangle at C
tan A = 1
⇒ To verify :- 2 sin A cos A = 1.
⇒ Solution:- In ∆ ABC
tan A = 1
BC/AC = 1
BC = x & AC = x
By Pythagoras theorem
AB^2 = AC^2 + BC^2
AB^2 = x^2 + x^2
AB = √2x
sin A = BC/AB
= x/√2x
= 1/√2x
cos A = AC/AB
= x/√2x
= 1/√2x
2 sin A cos A =
2 × 1/√2 × 1/√2
= 1
Hence verified!
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