Question

in a right triangle ABC right angle is AC BC + CA is equal to 23 cm and BC-CA is equal to 7 cm then find sinA and tanB​

Answer 1

Answer:

sinA = 15/17 , tanB = 8/15

Step-by-step explanation:

let BC = y and AC = X then

y + x = 23

y - x = 7

2y = 30 ---> y = 15 , x = 8

BC = 15 cm , AC = 8 cm , AB = $\sqrt{225+64}$ = 17