In a right triangle ABC right angled at B, AB = 3k, BC = 4k and tanA = 4/3, find other trigonometric ratios of the angle A
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hyp AC=5k
base AB=3k, perp BC=4k
now tanA=4/3, so cotA=3/4
sinA=BC/AC=4/5? So cosecA=5/4
similarly CosA=3/5 so SecA =5/3
base AB=3k, perp BC=4k
now tanA=4/3, so cotA=3/4
sinA=BC/AC=4/5? So cosecA=5/4
similarly CosA=3/5 so SecA =5/3
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