In a right triangle abc,right-angled at b,bc=12cm and ab=5cm.the radius of the circle inscribed in the inscribed in the triangle(in cm) is
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2 centimetres is the radius of the circle inscribed in the triangle
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Right angle triangle ABC , with ∠B = 90°.
BC = 12 cm. AB = 5 cm
AC² = BC² + AB² = 169 => AC =13 cm
Area of ΔABC = 1/2 * AB* BC = 30 cm²
Hence, s * r = Area = 30 cm²
(AB+BC+CA)/2 * r = 30
r = 30 * 2/(12+5+13) = 2 cm
BC = 12 cm. AB = 5 cm
AC² = BC² + AB² = 169 => AC =13 cm
Area of ΔABC = 1/2 * AB* BC = 30 cm²
Hence, s * r = Area = 30 cm²
(AB+BC+CA)/2 * r = 30
r = 30 * 2/(12+5+13) = 2 cm
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