In a right triangle ABC, right-angled at B, BC=12CM and AB=5cm.The radius of the circle inscribed in the triangle(in cm) is?
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Answers
Answered by
1
b=90
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
How is this statement possible? diameter of circle = ab+bc-ac
kk
ac=ab+bc
send ac to left side
ab+bc-ac
kkkk.
Answered by
1
b=90
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
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