Question

In a right triangle ABC, right angled at B, find AC, if (i) AB = 10 cm. BC = 24 cm (ii) AB = 7 cm, BC = 24 cm​

Answer 1

Given :

A right triangle ABC, right angled at B .

• (i) AB = 10 cm. BC = 24 cm .
• (ii) AB = 7 cm, BC = 24 cm .

To Find :

• Length of AC ?

Solution :

(i) AB = 10 cm. BC = 24 cm :

Using Pythagoras Theorem :

$\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\longmapsto\tt{{(AC)}^{2}={(10)}^{2}+{(24)}^{2}}$

$\longmapsto\tt{{AC}^{2}=100+576}$

$\longmapsto\tt{{AC}^{2}=676}$

$\longmapsto\tt{AC=\sqrt{676}}$

$\longmapsto\tt\bf\purple{AC=26\:cm}$

(ii) AB = 7 cm, BC = 24 cm :

Using Pythagoras Theorem :

$\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\longmapsto\tt{{(AC)}^{2}={(7)}^{2}+{(24)}^{2}}$

$\longmapsto\tt{{AC}^{2}=49+576}$

$\longmapsto\tt{{AC}^{2}=625}$

$\longmapsto\tt{AC=\sqrt{625}}$

$\longmapsto\tt\bf\pink{AC=25\:cm}$

Answer 2

Answer:

as 24 square 576 and addition of 100 gives 676 which is 26 square..

and same adding 49 to 576 for next q gives 625 which is the square of 25.

Hope it helps you sister naanum Tamil dhaa.

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