In a right triangle ABC right angled at B, if AB = 5 cm and AC = 13 cm, then the value of sin A is:
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Answer:
AC = 13cm
AB = 5 cm
in ABC, B = 90⁰
h² = b²+ p²
13² = BC² + 5²
169-25 = BC²
144 = BC²
12² = BC²
BC = 12 cm
sinA = BC/AC
= 12/13
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