Question

in a right triangle abc right angled at b if sin a =3/5 find all six trigonometric ratios​

Answer 1

HeRe Is Your Ans ⤵

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{ H² = P² + B²

B² = 5² - 3²

B = 4 }

➡Sin A = P / H = 3 / 5

➡Cos A = B / H = 4 / 5

➡Tan A = P / B = 3 / 4

➡Cot A = B / P = 4 / 3

➡Sec A = H / B = 5 / 4

➡Cosec A = H / P = 5 / 3

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Answer 2

Step-by-step explanation:

By pythagoras theorem,

=> h² = p² + b²

=> 5² = 3² + b²

=> 25 - 9 = b²

=> 16 = b²

=> 4 = b

Therefore,

sin A = 3/5

cos A = 4/5

tan A = 3/4

cosec A = 5/3

sec A = 5/4

cot A = 4/3