Question

In a right triangle ABC, tan(A) = 3/4. Find sin(A) and cos(A).

Answer 1

heya dear friend .....

check the above attachment .

I hope that will help uh !! :)

Answer 2

See the image

Given,

In a right triangle ABC, tanA =p/b = BC/AB 3/4

first of all , we know that

sinA = BC/AC = p/h

and

cosA = AB/AC = b/h

now,

using Pythagoras law ,

AC² = AB² + BC²

=> AC² = 4² + 3²

=> AC = √ 16 + 9

=> AC =√ 25

.°. AC = 5

we found AC = 5 .

so ,

sinA = 3/5

CosA = 4/5

thanks

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