Question

In a right triangle ABC with angle A equal to 90°, find angle B and C so that sin(B) = cos(B)

Answer 1

Answer:

Let b be the length of the side opposite angle B and c the length of the side opposite angle C and h the length of the hypotenuse.

sin(B) = b/h and cos(B) = c/h

sin(B) = cos(B) means b/h = c/h which gives c = b

The two sides are equal in length means that the triangle is isosceles and angles B and C are equal in size of 45°.

Answer 2

Step-by-step explanation:

sinB=cosB

We know that these are equal at 45°

B=30°

In ABC

A+B+C=180°

90°+30°+C=180°

C+120°=180°

C=180-120°

C=60°