Math, asked by Arunasandeep7871, 10 months ago

In a right triangle FGH angle G=90 find cosec f

Answers

Answered by anubhavdash567
0

Answer:

FH/GH

HDKCKFKFUSYMDITETJARH QARUQ WRIA

KGAJGARJAJDAJFhrq

Answered by vivekadithya55
0

Answer:

Step-by-step explanation:

Answer:

\text{The value of cosec B is }\frac{2}{3}

Step-by-step explanation:

\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}

We have to find the value of cosec B.

As A+B=90°

⇒ A=90°-B

sec A=\frac{2}{3}

sec(90^{\circ}-B)=\frac{2}{3}

\text{As }sec(90-\theta)=cosec \theta

cosec B=\frac{2}{3}

\text{Hence, the value of cosec B is }\frac{2}{3}

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