In a right triangle FGH angle G=90 find cosec f
Answers
Answered by
0
Answer:
FH/GH
HDKCKFKFUSYMDITETJARH QARUQ WRIA
KGAJGARJAJDAJFhrq
Answered by
0
Answer:
Step-by-step explanation:
Answer:
\text{The value of cosec B is }\frac{2}{3}
Step-by-step explanation:
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}
We have to find the value of cosec B.
As A+B=90°
⇒ A=90°-B
sec A=\frac{2}{3}
sec(90^{\circ}-B)=\frac{2}{3}
\text{As }sec(90-\theta)=cosec \theta
cosec B=\frac{2}{3}
\text{Hence, the value of cosec B is }\frac{2}{3}
Similar questions