Question

in a right triangle having sides equal to 5cm ,12cm and 13cm the length of the altitude drawn on the hypotenuse will be​

Answer 1

Step-by-step explanation:

I couldn't type in here so have attached a photo

Answer 2

Solution :-

we know that,

• Area of ∆ = (1/2) * Base * Perpendicular height .

so,

→ Area of right angled ∆ = (1/2) * 12 * 5 = 30 cm²

now, let us assume that, the length of the altitude drawn on the hypotenuse is x cm .

then,

→ Area of right angled ∆ = (1/2) * hypotenuse * altitude .

A/q,

→ (1/2) * 13 * x = 30

→ 13x = 60

→ x = (60/13) cm (Ans.)

Hence, the length of the altitude drawn on the hypotenuse is (60/13) cm .

Shortcut :-

• Length of of the altitude drawn on the hypotenuse of a right angled ∆ = (P * B)/H

given that,

→ P(perpendicular) = 5

→ B(Base) = 12

→ H(Hypotenuse) = 13

so,

→ Length of of the altitude drawn on the hypotenuse of a right angled ∆ = (P * B)/H = (5 * 12)/13 = (60/13) cm (Ans.)

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