Question

In a right triangle, if angle A is acute and cot A=4/3, find the tan A, sin A, secA.

Answer 1

Answer

cotA=4/3

So, Here, we have base/perpendicular =4/3

Base=4x

Perp.=3x

Now, hypotenuse = √4x² + 3x² = √25x= 5x

so,according to the ratios.

tanA=3/4

SinA=3/5

SecA=5/4