Question

In a right triangle if the ratio of sin∆ is 3/5, the value
of cos∆ will be-​

Answer 1

Step-by-step explanation:

sin ∆ = 3/5

sin²∆+cos²∆ =1

cos²∆=1-sin²∆

cos²∆=1-9/25

cos²∆=16/25

cos∆=±4/5

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Answer 2

Step-by-step explanation:

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