in a right triangle right angled at B AC is equal to 13 cm and ab is equal to 5 cm then find sin a
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Answer:
AB2+ BC2= AC2
5 square + BC2 = 13 Square
BC2 = 169 - 25
BC = 12 cm
SinA = BC/AC
SinA = 12/13
Step-by-step explanation:
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