In a right triangle right angled at B, if 4 cosec A = 5 then verify that 1 + tan²A = sec²A.
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Answer:
from the question we get cosec A=5/4
Step-by-step explanation:
by triangle we get,tan A =4/3,,secA=5/3
first finding L.H.S value which is 1+tan^2 A
L.H.S
1+(4/3)^2
1+16/9
25/9
Now R.H.S
(5/3)^2
25/9
which is L.H.S value
therefore L.H.S= R.H.S
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